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questions 35,36,37,38, and 39 all refer to the problem below In the reaction of iron (III)...

questions 35,36,37,38, and 39 all refer to the problem below

In the reaction of iron (III) sulfate and barium hydroxide,

Fe2(SO4)3 + 3Ba(OH)2 -> 3BaSO4 + 2Fe(OH)3.


If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2.

Molar masses

Fe2(SO4)3 = 399.91

Ba(OH)2 = 171.35

Fe(OH)3 = 106.88

37. How many grams of Fe(OH)3 will be produced if both iron (III) sulfate and barium hydroxide were used in the reaction?

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Answer #1

Jt i& gven that feal Soa)s 2 ba So4 t2feCon3 +3 Balon2 7Molar Man o Pero43= 319.9) Ba CoMl2 17H 31 fe(onls /06: 88 aud amount

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