Question

EME 212 e 10 V-Eon =.6V A VeC 3 V M V in loon 5mA .5m ま204 ROat Pin a)tnd De operatiz vaues Vout vin

Rout is pointing towards the emitter

Answer 1

Guen B10 VA= D , VgC,on = 0.6V, Vcc 3V SVCC 2G 2 Nout o.sm 0-Sma TEI 0-Sna, It2 = 0.SmA B)2R = TE kno We 0.SmA TE2 O-O454 mA D TE2-ae2 o.S-O.O4 S4S o.454S mA o.SmA TE D Te=IE\ - 2eI = O- 4SSSC mA O.SA fo Rusistor 3 ú Icuta62 = V acrosS 26 O-Sx1D x2* 10 SD VCEI O.2v. 20 2 = 3V. 20GtIDG Ng-VE VBEDO 0.6- VEI VB -0.6 VCEI t VEI VBE Dn 0.6 = UB2- NE2 VE 2 .6-0.6 = \V Vei= -6U VE2= VCEIO.2V, Vee2=

siqnal Bmau Dc -C m oean De vottag shortcol, Rour ein -o Nout Rouk コ(329 33) + 3 0.US4SMA 8RL 0.O 181g Rou ROut a&- \\SSQ ReI -o Vout Nout Aue2 Au x Goan - x Rout AuI UT Au 20.99 Common collec tor anplib'ei] GainAue x Au 2 = 20.99 VIV