Homework Answers
a)
The balanced chemical equation for the neutralization reaction between HCl and NaOH is as follows
HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) + Heat
Calculate the heat of solution as given below
Qsolution = m*c*∆T
where, m = mass of solution (Mass of HCl + mass of NaOH) = (40 g HCl + 100 g NaOH) = 140 g
(Since the density of solution = 1 g/mL)
∆T = Tf - T1 = 46.0 - 20.0 = 26°C
Qsolution = (140 g)(4.184 J/g°C)(26°C)
= 15229.76 J
= 15.23 kJ
b)
The heat released by the reaction is Qsolution. Thus, according to law of conservation energy the relation between Qsolution and Qreaction is as
Qsolution + Qreaction = 0
or Qreaction = - Qsolution = -15.23 kJ
c)
Calculate the number of moles of HCl using following formula
No. of moles of HCl = Molarity x Volume in L
= (2.50 M)(40 x 10-3 L)
= 0.1 mole
The ∆H can be calculated as
∆H = (Qreaction)/(No. of moles of HCl)
∆H = (-15.23 kJ)/(0.1 mole)
∆H = - 152.3 kJ
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