2 ) B) -71 kJ C) +113 kJ D) -113 kJ E) -389 kJ -1) Which...

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2 ) B) -71 kJ C) +113 kJ D) -113 kJ E) -389 kJ -1) Which of the following orders of electronegativity is incorrect?! A) Se <S

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Answer 1

Answer #1

31. C) N < P < S

The order of electronegativities is wrong in this set.

The electronegativity down a group decreases from top to bottom as the electrons enter into new shells down each period.

In a period from left to right, the electronegativities increases as the upcoming electrons enter into the same shells.

In the given order Nitrogen and Phosphorous belongs to the same group. Nitrogen present at the top of the group with the maximum electronegativity among the elements of its group. The phosphorous is the second element in the nitrogen family. Sulphur is the element right to the Phosphorous.

Thus phosphorous and sulphur are in the same period. As per the electronegativity trend in a period, sulphur is more electronegative than phosphorous which is less electronegative than nitrogen as nitrogen is present up in the nitrogen family.

Therefore the correct trend of electronegativities for the given set of atoms is

P < S < N.

In all the remaining sets, the electronegativity trends are followed by atoms and they are placed in correct order.

32. orbital (b)

The shape of p-orbital is dumb bell. We should figure out 4p_z orbital in the given diagrams.

Given orbitals (a) and (b) are dumb bell shaped orbitals and thus these are p-orbitals

(c) and (d) are double dumb bell shaped orbitals and hence these are not p-orbitals.

There are three types of p-orbitals p_x , p_y and p_z

In a p_x orbital, the dumb bell lobes situate along x - axis

In a p_y orbital, the dumb bell lobes situate along y - axis

In a p_z orbital, the dumb bell lobes situate along z - axis

In the given orbital (b) the lobes of dumb bell are situated along z - axis and hence this is the required 4p_z orbital.

The shell number 4 in 4p_z has nothing to do with the shape and hence we need not to consider it.

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