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In 1911, Ernest Rutherford and his assistants Geiger and Marsden conducted an experiment in which they scattered alpha particles (nuclei of helium atoms) from thin sheets of gold. An alpha particle, having charge ÷2e and mass 6.64 × 10-27 kg, is a product of certain radioactive decays. The results of the experiment led Rutherford to the idea that most of an atoms mass is In a very small nucleus, with electrons in orbit around it. Assume an alpha particle, initially very far from a stationary gold nucleus, is fired with a velocity of 1.52 × 107 m/s directly toward the nucleus (charge +79e). What is the smallest distance between the alpha particle and the nucleus before the alpha particle reverses direction? Assume the gold nucleus remains stationary. fm

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Answer #1

Concepts used in the answer:- principle of energy conservation and potential energy due to configuration of charges is used

om energy conser vahon, Et = Ef ag (6.64x10-27

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