Question

If the initial amount of strontium-90 ordered was 4.0 grams, how much will remain after 5 half-lives have occurred? (5 pts.)
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Solution:

Half live: The time taken for one half of the mass of radio active substance reduced is called as half live.

I half live -----> 4.0 g Sr-90 is reduced to 2.0 g

II half live -----> 2.0 g Sr-90 is reduced to 1.0 g

III half live -----> 1.0 g Sr-90 is reduced to 0.5 g

IV half live -----> 0.50 g Sr-90 is reduced to 0.25 g

V half live -----> 0.25 g Sr-90 is reduced to 0.12 g (or) 1.2*10^-1 g

A:- 1.2*10^-1 g remains after five half lives of Sr-90.

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