6)
Given:
T1 = 25 oC
=(25+273)K
= 298 K
T2 = 35 oC
=(35+273)K
= 308 K
K1 = 1.35*10^2 s-1
Ea = 55.5 KJ/mol
= 55500 J/mol
use:
ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)
ln(K2/1.35*10^2) = (55500.0/8.314)*(1/298 - 1/308.0)
ln(K2/1.35*10^2) = 6675*(1.09*10^-4)
ln(K2/1.35*10^2) = 0.7273
(K2/1.35*10^2) = e^(0.7273)
(K2/1.35*10^2) = 2.069
K2 = 2.80*10^2 s-1
Answer: E
Only 1 question at a time please
6) is the 102 -1 at 250 °C. What 6) A particular first-order reaction has a...
A particular first-order reaction has a rate constant of 1.35 × 102 s−1 at 25.0 ∘C. What is the magnitude of k at 75.0∘C if Ea = 55.5 kJ/mol. PLEASE SHOW WORK
102 s-1 at 25.0 °C. What is the 21) 21) A particular first-order reaction has a rate constant of 1.35 magnitude of k at 75.0 °C if Ez = 55.3 kJ/mol? A) 2.24104 B) 2 49 * 106 C) 135 x 102 D) 433 E) 3.34 * 103
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questions 9,10 and 11 please! thank you lying 0.23 mol of hypochlorous acid and 0.27 mol of sodium fent to yield 1.00 L of solution. The addition of 0.05 mol of NaOH to this to increase slightly. The pH does not increase drastically because the present in the buffer solution. The Ka of hypochlorous acid is A solution is prepared by dissolu hupachlorite in water sufficien buffer solution causes the pH toinen NaOH reacts with the 30.10-8 Ohypochlorous acid B)...
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107) What is the magnitude of k for a first-order reaction at 75.0 °C if Ea = 95.1 kl/mol and rate constant is 1.35 x 102 s-1 at 25.0 ℃? A) 1.36 x 10 B) 4.28 x 106 C) 3.85 104 D) 3.36 x 104 E) 745 108) Which of the followino exnressions is the correct equilibri
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