Question

1. Han Solo and Chewbacca are attempting to break into an Imperial hangar on the forest moon of Endor. Before breaking in, they test the electric field all over the hangar, in order to ascertain whether there are electrically charged weapons inside. The hangar has flat sides and floor, but the roof is symmetrically slanted, as shown in the diagrams belovw Perspective view of hangar: right roof <0, 0,+20.0> N/C left roof <0, 0,-10.0> N/C Eback <-30.0, 0, 0> N/C E, left <0, +70.0, 0> N/C 5.00m Eright <0, +40.0, -40.0> N/C 10.0m 50.0m Z A 15.0m 15.0m 30.0m bottom <o, +50.0, -50.0> N/C x Front view of hangar: <+60.0, 0, 0> N/C Top view of hangar: 5.00m Z A 10.0m 15.0m 15.0m 50.0m 30.0m 30.0m

Answer 1

Q_left roof = -10 times (15 times 50) = -7500 Nm^2/C [here area uptake to E is taken (that is E time s(A cos theta) A cos theta is uptack area phi_right roof = 20 times (15 times 50) = 15000 Nm^2/C Q_back = -30 times { - (10 times 30 + 1/2 times 30 times 5)} = 11250 NM^2/C Q_front = 60 times {10 times 30 + 1/2 times 30 times 5} = 225500 NM^2/C Q_left = 70 times [- 10 times 50] = -35000 Nm^2/C phi_right = 40 times 10 times 50 + (- 40 times 0) = 2000 Nm^2/C phi_bottom = 0 times 50 + (- 50) times (- 30) times 50 = 75000 Nm^2/C total flux phi_Total = 101250 Nm^2/C It comes out +ve from Gauss Law Q/epsilon_0 = total flux Q = epsilon times 101250 C = 8.96 times 10^-7 C