Question

Bonus 3. Give the structures of the two products for addition reaction of HCl to 3-methyl-1-pentene (1 point). Point out which one is the major product, and explain why! (Hint: dont forget carbocation rearrangement) 4. The transformation of the alkyl chloride shown below into the alcohol can be accomplished in two steps. Show the synthetic scheme to finish the conversion. (1 point) Он Br

Answer 1

9.3. Amo- the reaction of 3-methyl-1-pentene with this be uw - th=41-44-43-143 CH2 - CH₂ - 91-442-413 : tch-CH2-C-CH-CH3 city (3-methyl-1-pentene) B minor) major) Mechanism - -a Bimota A E . CH₂=CH-CH-CH2-442 Ch & cut-CH3 O (Secondary carbocation) 5. hybride Shitt atro (Rearrangement of (A-band election aftack" the hyrogen of H4) Carbocation) hot CH3 CH2 - C -4 -443 C CH₃-CH2-C- CH2 CH3 . CH3 . . CTertiary caskocation) . The major product is formed from fentiasy carbocation intermediate instead of secondary easbocation, ht. Since tertiary caskocation is very stable die to having more inductively donating alkyl group. -

8.4. Ans, the conversion of alkyl chloride and to aleshol is ginsen below, KOH a rasot o dilute Hasau yot alkene step i mechanism. In presence of alcoholic koch, alkyl halide gives elimination product kost nact with C H5OH and form G4500, which is a string base than of the Ca H5oo n t kd & H2O + 2H5OH (Chs of abstract the phyosogen) step in mechanism Alkene react with dil. Hisou and give alcohol. Whe reaction followed by the formation of a stable easko catton intermediate H+ (brom Hiso) able carbocation)