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If 5.00 L of water vapor at 50.2 C and 0.121 atm reacts with excess iron, how many grams of iron(III)oxide will be produced?
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solutions :- first to find mass of water vapor volume al water vapor, v= 5-002 Temperature, 5=50-2°C = 3 23.2k Pressure, p= 0= 5ug weiter vapor maut to produce 159.69 g 6e 203 : 0.410g water vapor will produce = 159.69 x 0-410 g bezez = 1.2125 g bezu

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