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Assume 117 grams of iron(III) oxide, Fe o reacts with excess hydrogen, H. The problem requires that you determine the mass of
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Solution : The Reaction given in the question is, 17g of Feas react with encess onygun, The Reaction is, Fe (5) + 3 H2 (g) 2117 Fe 2 O 3 x I mol Fea, 159.709 fears 2 mol Fe 1 mol Feas 55.85g Fe I molte = 112g x mol Fe 3 a mol Fe 55-85 Fe 159.70g Fe

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