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The speed of an object undergoing 1-dimensional motion is given by the following equation:

v squared equals open parentheses 7 1 over straight s squared close parentheses x squared

What is the magnitude of the acceleration of the object (in m/s2) at x = 10 m?

I got this much

But can't figure out how to deal with both variables

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Answer #1


2 チχ dt -1 Agam diafereanati ut l we get

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