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3. (20 points) Let A, B, and C be 3 events with probabilities given in the figure below. Find P(AlBc n C) 0.20 0.1 凸 0.1 0.2
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P(A|Bc intersection C)

P(A|Bc Intersection C) = P(A int Bc int C) / P(Bc int C) [this is the formula : P( X|Y) = P(X intersection Y)/ P(Y)]

The common area between A and Bc and C = .10

The common area between Bc and C = .30

P(A|Bc Intersection C) = P(A int Bc int C) / P(Bc int C)

= .1 / .1+.2

= 1/3

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