work done by the gravitational force,
W= mgh = 68.1*9.8*38.9
W = 25961.082 J
Although the net work done on the body will be zero, since at terminal velocity, the net force on the body will be zero, and
the net work done will be equal to the product of net force and the displacement
hence the net work done on the body will be zero
to 'Energy &Work A 68.1 kg skydiver reaches work is done on the skydiver? a terminal...
A skydiver jumps out of an airplane at a high altitude and reaches terminal speed. Which of the following statements about the falling skydiver at terminal speed is FALSE? The air resistance force does negative work on the skydiver. The gravitational force on the skydiver must be larger than the air resistance force in order to maintain a downward velocity. At terminal speed, the kinetic energy of the skydiver is constant. The thermal energy of the skydiver-Earth-atmosphere system is increasing....
Energy & Work A elevator has 120505 J of work done on it to ralse it 5.7 m, how much force is needed to lift the elevator (and passengers) if it rising at a constant speed? Answer: 21141.23 N Check Correct Marks for this submission: 1.00/1.00. What is the mass of the elevator (and passengers) if it rising at a constant speed? ofAnswer: 120505 kg Check Incorrect Marks for this submission: 0.00/1.00
For 7-9: A skydiver falls ot constant, terminal velocity in the presence of air resistance 7. (3 pts) The net work done on the skydiver is.. a) positive b) negative c) zero 8. (3 pts) The non-conservative work done on the skydiver is.. a) positive b) negative c) zero 9. (3 pts) The mechanical energy of the skydiver is. a) conserved c) decreasing b) increasing For each problem, show all work for full credit. Use at least three significant figures...
A skydiver of mass m jumps from a hot air balloon and falls a distance d before reaching a terminal velocity of magnitude v . Assume that the magnitude of theacceleration due to gravity is g .-What is the work (Wd) done on the skydiver, over the distance , by the drag force of the air?-Find the power (P d) supplied by the drag force after the skydiver has reached terminal velocity v.
please help with 8.5, 8.6, 8.7, 8.8 work done by gravity positive, negative, or zero (c) After the block reaches the bottom, and continues sliding back up the bowl until it comes to rest, is the additional work done by gravity positive, negative, or zero? (d) It the bowl is ot frictionless, will the block slide back up to the same height it (c) When friction is present, and after the block reaches the bottom, is the additional was released...
A 50kg skydiver jumps out of an airplane. We assume that the forces acting on the body are the force of gravity and a retarding force of air resistance with direction opposite to the direction of motion and with magnitude cv^2 where c=.1275 kg/m and is the velocity of the skydiver at time t (and upward is positive velocity). The gravitational constant is 9.8 m/s^2 . a) Find a differential equation for the velocity. b) Determine the terminal velocity in...
A 90-kg (including any equipment) skydiver drops out of a plane. Using an air density of 1.0 kg/m3, a frontal surface area of 1.0 m2, and a drag coefficient of 0.8, what will the skydiver's terminal velocity be? A. Less than 50 m/s B. Between 50 and 100 m/s C. Between 100 and 150 m/s D. More than 150 m/s v= square root -2 (90) (-9.81)sin90/.8(1.0)(1.0)
Two skydivers are holding on to each other while falling straight down at a common terminal speed of 63.10 m/s. Suddenly, they push away from each other. Immediately after separation, the first skydiver (who has a mass of 89.30 kg) has the following velocity components (with "straight down" corresponding to the positive z-axis): v_1, x = 4.930 m/s v_1, y = 4.750 m/s v_1, z = 63.10 m/s What are the x- and y-components of the velocity of the second...
Studio 2053C Fall 2016: Energy and Work An eraser of mass m = 0.120 kg is released from rest at a distance L = 0.750 m from the bottom of a whiteboard, which is inclined at an angle of 30.0° to the horizontal. The coefficient of kinetic friction between the eraser and whiteboard is μ,-0.125. Use g= 9.81 m/s (1) What is the work done by gravity as the eraser moves from where it is released to the bottom of...
please clear hand writing and show all the work thanks in advance Problem 3: Terminal velocity A hailstone of mass m = 6 x 10-4 kg falls under the effect of gravity. It also experiences a drag force of magnitude FD = nu?, where v is the hailstone's velocity and the coefficient 7 for the particular hailstone under consideration is equal to n= 3 x 10-5 kg/m. (a) Calculate the terminal velocity of the hailstone. (b) If the hailstone falls...