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Main Menu Contents Grades Course Contents ... hw13 10.22 - Rotational Kinetic Energy: Work and Energy Revisited What is the f
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Answer #1

here,

let the final velocity of the hoop is v

Using conservation of energy

0.50 ( I * w^2) + 0.50 m * v^2 = mgh

0.50 * m * r^2 * (v/r)^2 + 0.50 * m * v^2 = mgh

m * v^2 = mgh

v^2 = 9.8 * 5.6

v = 7.41 m/s

the speed of the loop at the bottom is 7.41 m/s

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