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Main Menu Contents Grades Course Contents ... hw13 10.11T - Dynamics of Rotational Motion Rotational Inertia • Timer Notes Ev
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Answer #1

net moment of inertia

= moment of inertia of cylindrical part + moment of inertia of two rod

= 0.5 M R^2 + 2 * (1/3) m L^2

= 0.5* 43* 0.122^2 + (2/3)* 3* 0.96^2

= 2.163 kg m^2

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Comment before rate in case any doubt, will reply for sure.. goodluck

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