Question

Draw the alkyne formed when 1,1-dichloro-4-methylpentane is treated with an excess of a strong base such...

Draw the alkyne formed when 1,1-dichloro-4-methylp

Draw the alkyne formed when 1,1-dichloro-4-methylpentane is treated with an excess of a strong base such as sodium amide. (Give the neutralized alkyne product, not the acetylide salt.)

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Concepts and reason

Geminal dihalides are compounds containing carbon atoms with two halogens attached to it. Alkynes are compounds containing carbon-carbon triple bonds and are synthesized when geminal dihalide undergoes an elimination (dehydrohalogenation) reaction using a strong base such as sodamide (NaNH2).\left( {{\rm{NaN}}{{\rm{H}}_2}} \right).

Fundamentals

Sodamide (NaNH2):\left( {{\rm{NaN}}{{\rm{H}}_2}} \right): The compound sodamide is an inorganic compound and it is a strong base.

It is used in elimination reactions such as dehydrohalogenation (removal of Hydrogen halide).

The reaction scheme for the dehydrohalogenation of dihaloalkane using sodamide is given below:

NaNH)
Excess

The reaction mechanism for the removal of hydrogen chloride is given below:

Na
NH2
Hн
+ NH3 + NaCl
E2 reaction

The reaction of sodamide with alkenyl chloride is given below:

Na
NH2
+ NH3 +
NaCl
E2 reaction

Ans:

The alkyne formed when 1, 1-dichloro-4-methylpentane is treated with an excess of a strong base such as sodium amide is given below:

NaNH,
Excess

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