Question

Tutored Practice Problem 19.2.4 cartes Calculate solubility in the presence of a common ion. Calculate the solubility of Ag,PO, (a) in pure water and (b) in a solution in which [POP-1=0.163 M. Solubility in pure water - Solubility in 0.163 M PO 3- = Check & Submit Answer Show Approach pe here to search 0 PM

Answer 1

Solubility in pure water = 4.68 x 10^-6M

Solubility in 0.163 M PO₄^3- = 1.43 x 10^-7M

Explanation

(1.) K_sp Ag₃PO₄ = 1.3 x 10^-20

Let molar solubility of Ag₃PO₄ = s

[Ag₃PO₄] = s

[Ag⁺] = 3 * [Ag₃PO₄]

[Ag⁺] = 3s

[PO₄^3-] = [Ag₃PO₄]

[PO₄^3-] = s

K_sp Ag₃PO₄ = [Ag⁺]³[PO₄^3-]

1.3 x 10^-20 = (3s)³ * (s)

1.3 x 10^-20 = 27s⁴

s = (1.3 x 10^-20 / 27)^1/4

s = (4.8 x 10^-22)^1/4

s = 4.68 x 10^-6 M

molar solubility of Ag₃PO₄ = s = 4.68 x 10^-6 M