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Concepts and reason

1H NMR Spectroscopy:

Nuclear magnetic resonance(NMR)
spectroscopy is one of the techniques in the analytical chemistry that is widely used to determine the purity of sample and to predict the structure of the organic compounds.

The NMR
spectroscopy is phenominal that is observed when frequency of nuclei of atoms (sample) resonates with frequency of rotating magnetic field.

HNMR
Spectroscopy determines the different types of hydrogens (chemically non-equivalent hydrogens) present in a molecule.

Fundamentals

1H NMR Spin-Spin Coupling Patterns:

Number of neighboring hydrogens (chemically non-equivalent)

n

Number of peaks

()

Splitting Name

Peak heights ratio

0

1

Singlet

1

2

Doublet

2

3

Triplet

3

4

Quartet

1:33:1

The formula to calculate the degree of unsaturation:

_2C+N-H-X+2
where,
DoU is the degree of unsaturation,
C is the number of carbons,
N is the number of nitrogens,
H is

The given molecular formula :
CHO
Doll-(2x7)+0-16-0+2
2
Dou - 14–16+2
DoU =0(It has no double bond)

The H NMR
spectral data is given below:

Chemical shift

Multiplicity

Around 0.9ppm

triplet

Around 1.38ppm

quartet

Around 1.42ppm

singlet

Chemical shift – 1.42ppm: The H NMR
spectra shows quartet at 1.42ppm is due to the splitting of three hydrogens attached to carbon and there are three identical methyl groups.

Example:
1.42ppm (quartet)
HC-CH3

Chemical shift – 1.38ppm: The singlet peak is observed at 1.38ppm disappear after shaking with proton at group of tertiary alcohol.

Chemical shift – 0.9ppm: The H NMR
spectra shows triplet at 0.9ppm is due to the splitting of two hydrogens attached to carbon shows this peak and three identical ethyl groups.

Example:
0.9 ppm (triplet)
H2C—
CH3

Therefore, the compound has one alcoholic group and three identical CH,CH,
groups attached to the tertiary carbon atom.

The structure of the compound with assignment of chemical shift values is given below:

0.9ppm (triplet)
1.42ppm (quartet)
HO-CH2
1.42ppm (quartetty
* Hąc—¢—OH
C
0.9ppm (triplet)
CH
1.42ppm (quartet)
0.9ppm (tripl

Ans:

The structure for the given organic compound is

CH2CH3
H3CH2C—C—OH
CH2CH3

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