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9.15 Consider a hydrogen electrode in HBr(aq) Estimate the change in the electro de potential when the solution is changed fr
2019 ELECTROCHEMISTRY TUTORIAL 9.25 (a) Calculate the standard potential of the cell Hg(1)|HgCl2(aq)||TINO:(aq) |TI (s) at 25
9.15 Consider a hydrogen electrode in HBr(aq) Estimate the change in the electro de potential when the solution is changed from 5.0 mmol dm-3 to at 25°C operating at 1.45 bar. 15.0 mmol dm3 9.16 Devise a cell in which the cell reaction is: Mn(s) + Cl2(g) MnCl2(aq). Give the half-reactions for the electrodes and from the standard cell potential of +2.54 V deduce the standard potential of the Mn2/Mn couple. 9.17 Write the cell reactions, electrode half-reactions and Nernst equations for the following cells: (d) Pt(s) Cl2(g)|HCI (aq)| |HBr(aq) |Br2(lOPt(s) (e) Pt(s)|Fe3 (aq),Fe2 (aq)||Sn4 (aq),Sn2 (aq)/Pt(s) 9.18 Use the standard potentials of the electrodes to calculate the standard potentials of the cells in Exercise 9.17. 9.19 Devise cells in which the following are the reactions. In each case state the value for v to use in the Nernst equation. Pb(s) (a) Fe(s) + PbSO4(aq) FeS04(aq) + (b) Hg2Cl2(s) + H2(g) -2 HCl(aq) + 2 Hg() 9.20 Use the standard potentials of the electrodes to calculate the standard potentials of the cells in Exercise 9.19. are 9.23 State what you would expect to happen to the cell potential when the following changes made to the corresponding cells in Exercise 9.17. Confirm your prediction by using the Nernst equation in each case. (d) The concentration of HCl is increased. (e) Some iron(III) chloride is added to both compartments.
2019 ELECTROCHEMISTRY TUTORIAL 9.25 (a) Calculate the standard potential of the cell Hg(1)|HgCl2(aq)||TINO:(aq) |TI (s) at 25°C. (b) Calculate the cell potential when the molar concentration of the Hg2 ion is 0.230 mol dm-3 and that of the Tl ion is 0.720 mol dm-3. 9.26 Calculate the standard Gibbs energies at 25°C of the following reactions from the standard potential data in the Data section. (a) Ca(s)+ 2 H20(1)Ca(OH)2(aq) + H2(g) (b) 2 Ca(s)+ 4 H20 (I) 2 Ca(OH)2 (aq) + 2 H2(g) (c) Fe(s) +2 H2O (I) Fe(OH)2(aq) + H2(g) standard potential 9.32 Calculate the equilibrium constants of the following reactions at 25°C from data: (a) Sn(s)+ Sn (aq) 22 Sn2 (aq) SnBr2(aq)+ 2 Ag(s) (b) Sn(s) +2 AgBr (s)
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Answer #1

9.15 The electrode isn't working at standard conditions so we'll use Nernst Law to obtain the electrode potentials at both concentrations and then obtain the change:

0.06 logQ E= E°

that for the electrode half-reaction

2H 2e H2a); E = 0.00V (aq)

becomes:

0.06 Pна Pна -0.03log H+12 E 0.00V -log 2

so:

Pн 1.45 Е — - 0.03109Н+1? -0.031oд 5,0* 10-3). -0.1429V (5 [Н+2 2

1.45 0.03l0g15.0* 10 Pн E2=0.03logH+12 -0.1143V

E2 E 0.1143V (0.1429V) 0.0286

9.16 Solid manganese oxidizes, so this is the anodic reaction:

Mn(s)Mn 2e (ag)

Chlorine gas gets reduced so this the cathodic reaction

Cl2g)2e 2Cl (ag)

The standard cell potential is defined by:

EcellEnthode - Ennoda anode

we have to use the standard potential of the cell and of the Cl2/Cl- couple (cathodic reaction) to obtain the standard potential of the anodic reaction (Mn2+/Mn couple), so:

Eg - Eg cell cathode anode

Enod1.36V - 2.54V 1.18V anc

9.16:

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