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An experiment was designed to estimate the mean difference in weight gain for pigs fed ration...

An experiment was designed to estimate the mean difference in weight gain for pigs fed ration A as compared with those fed ration B. Eight pairs of pigs were used. The pigs within each pair were litter-mates. The rations were assigned at random to the two animals within each pair. The gains (in pounds) after 45 days are shown in the following table. Assuming weight gain is normal, find the 98% confidence interval estimate for the mean of the differences μd, where d = ration A - ration B. (Give your answers correct to two decimal places.)

Litter 1 2 3 4 5 6 7 8

Ration A 62 53 63 39 51 53 46 56

Ration B 54 43 60 33 44 48 38 47

Lower Limit =

Upper Limit =

0 0
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Answer #1

From the given data

Ration A Ration B D = Ration A - Ration B
62 54 8
53 43 10
63 60 3
39 33 6
51 44 7
53 48 5
46 38 8
56 47 9

Descriptive Statistics: D- Ration A - Ration B Variable D = Ration A-Ration B Total Count Mean StDev Variance Sum of Sum Squares 8 7.000 2.268 5.143 56.000 428.000

The 98% confidence interval estimate for the mean of the differences μd is

The 98% confidence difference between population means d ±ta,n-l4ys itt2W-l-7 ー=7 ±2.99 82.208 = (4.5962, 9.4037) V8

Lower Limit: 4.5962

Upper Limit: 9.4037

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