given
electric field E = 8.19*10^3 N/C
distance r = 0.283 m
from the relation
electric field due to a point charge is E = kq/r^2
here k = 9*10^9
q = Er^2/k
q = 8.19*10^3*0.283^2/9*10^9
q = 7.28*10^-8 C
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QUESTION 4) What is the direction of the electric field at point
A due to charge C in Fig. 1?
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at point A due to charge D in Fig. 1?
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