A ball is launched from ground level at 30 m/s at an angel of35 degrees above...

Question

Question

A ball is launched from ground level at 30 m/s at an angel of 35 degrees above the horizontal. How far does it go before it is atground level again?

A) 14 m

B) 21 m

C) 43 m

D) 86 m

E) 97 m

Answer 1

Answer #1

First determine the time:

y = V_it + 1/2at²

0 = 30m/s*sin(35)*t + 1/2*-9.81m/s²*t²

t = 3.51s

Then determine the distance:

x = V*t = 30m/s*cos(35)*3.51s = 86m

Answer 2

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