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A ball is launched from the ground at 21 m/s at an angle of 32 degrees...

A ball is launched from the ground at 21 m/s at an angle of 32 degrees above the horizontal. if the positive y direction is up, what is the y-component of the balls acceleration? you may ignore drag. (in m/s^2)

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Answer #1

a y = - 9.8 m/s^2 ( sign indicates down ward direction)

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Answer #2

This is motion under acceleration due to gravity.

So,the y-component of accleration will be downward g, i.e. -g m/sec2

where g = 9.81 m/sec2.

It is independent of the intial velocity of the particle.

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Answer #3

Acceleartion due to gravity acts downwards on the ball, therefore acceleration is in -y direction.

Note: It is independent of initial speed and angle of proection

Cheers

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Answer #4

Ball is free in the air so only gravitational froce is applied on the ball. And the value of the force is (mass)x(acceleration).

Acceleration is g = -9.81 m/s2  { minus sign because gravatational force is downward}

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