A man weighing 690 N and a woman weighing 400 N have the same momentum. What...

Question

Question

A man weighing 690 N and a woman weighing 400 N have the same momentum. What is the ratio of the man's kinetic energy Km to that of the woman Kw

Answer 1

Answer #1

m_m = mass of man = weight of man /9.8 = 690/9.8 = 70.4 kg

v_m = velocity of man

m_w = mass of woman = weight of woman /9.8 = 400/9.8 = 40.8 kg

v_w = velocity of woman

Given that :

Momentum of man = momentum of woman

m_m v_m = m_w v_w

(70.4) v_m = (40.8) v_w

v_w = 1.73 v_m eq-1

Ratio of KE is given as

Ratio = KE_m/KE_w = (0.5) m_m v_m² /((0.5) m_w v_w² ) = (70.4/40.8) (1/(1.73)²) = 0.58

Answer 2

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