Question

What mass of PCl5 will be produced from the given masses of both reactants?

P4+10Cl2 —> 4PCl5

20 g of P4 and 56 g of Cl2

Answer 1

Ans.

#Balanced Reaction: 1 P4 10 Cl2 4 PCls Step 2 mol of P4 Formation of product follows the stoichiometry of limitng reactant. 1.0 In balanced reaction, theoretical molar ratio of reactants mol of Cl2 10.0 Following stoichiometry 10 mol Cl2 forms 4 mol PCI5 = 20.000 g =123.895048 q mol Mass of P4 MW of P4 = 0.3159 mol moles of PCI5 formed x mol of Cl2 70.9054 g mol = 56.000 g Mass of Cl2 MW of Cl2 formed= mol x MW 0.3159 molx 208.2373 g mol-1 Mass of Step 1: Determine the limiting reactant PCI5 = 65.785 g 20.000 g Mass Mol of P4 0.1614 mol 123.895048 g mol 56.000 g MW Mass Mol of Cl2 MW 70.9054 q mol 0.7898 mol # Experimental molar ratio of reactants: 0.1614 mol mol of P4 1.000 mol of Cl2 0.7898 mol 4.893 #Comparing theoretical and experimental molar ratios of reactants, the experimental mol of Cl2 is less than its theoretical value of 10 mol while that of P4 is the limiting reactant. is kept constant at 1 moles. Cl2 So,