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Score: 0 or 3 pts 9.2.33 Use the data in the table below to complete parts (a) through (d) 11 of 15 (10 complete) 34 20 40 23 Click the icon to view details on how to construct and interpret residual plots. 43 26 59 28 53 26 21 29 28 23 뮬 (a) Find the equation of the regression line. Steps for Constructing a Residual Plot (Round to three decimal places as needed.) To construct a residual plot, make a scatter piot of (xy-), where y- is the residual of each y-value. If the resulting plot shows any type of pattern, the regression line is not a good representation of the relationship between the two variables. It it does not show a pattem, that is, the residuals fiuctuate about 0, then the regression line is a good representation. Be aware that if a point on the residual plot appears to be outside the pattern of the other points, then it may be an outlier Print Done

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Answer #1

From the given data,the following statistics are calculated.

\sum X=415

\bar{x} = 46.1111

\sum Y=223

\bar{y}= 24.8889

x - \bar{x} y - \bar{y} (x - \bar{x} )2 (x - \bar{x} )(y - \bar{y} )
- 8.1111 - 3.8889 65.7901 31.5432
- 12.1111 - 4.8889 146.679 59.2099
- 6.1111 -1.8889 37.3457 11.5432
- 0.1111 4.1111 0.0123 - 0.4568
- 3.1111 1.1111 9.679 - 3.4568
1.8889 3.1111 3.5679 5.8765
12.8889 3.1111 166.1235 40.0988
7.8889 - 1.8889 62.2346 - 14.9012
6.8889 1.1111 47.4568 7.6542
Total SSX = 538.8889 SP = 137.1111

Sum of Squares = SSX = 538.8889

Sum of Products = SP = 137.1111

b=\frac{SP}{SS_{X}}=\frac{137.1111}{538.8889}=0.2544

a=\bar{y}-b\bar{x}

=24.8889-(0.2544\times 46.1111)=13.1567

So,

Equation of the regression line is:

\hat{y}=0.254x+13.157

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