Select which process describes the following energy changes. (Ionization energy, electron affinity, bond enthalpy, or standard enthalpy of formation
A. F(g) + e- => F-(g)
B. F2(g) => 2F(g)
C. Na(g) => Na+(g) + e-
D. Na(s) + 1/2F2(g) => NaF(g)
A. F(g) + e- => F-(g)---------------------electron affinity
B. F2(g) => 2F(g)--------------------------------------bond enthalpy
C. Na(g) => Na+(g) + e---------------------------------ionization enthalpy
D. Na(s) + 1/2F2(g) => NaF(g)---------------------------------standard enthalpy of formation
Select which process describes the following energy changes. (Ionization energy, electron affinity, bond enthalpy, or standard...
Review Problem 8.065 Construct an enthalpy diagram with the following data to calculate the electron affinity of bromine. The standard heat of formation of NaBr is -360.0 kJ molº?. The energy needed to vaporize one mole of Br2(l) to give Br2(g) is 31 kJ mol-1. Energy needed to vaporize one mole of Na(s) is 107.8 kJ. The first ionization energy of Na is 495.4 kJ mol-1. The bond energy of Br2 is 192 k) per mole of Br- Br bonds....
Calculate the enthalpies of formation, ΔHfo, of the following group 1 fluoride compounds from their elements using the Born–Haber cycle. NaF RbF Number Number kJ ol kJ mol AHO, kJ/mol Sublimation of Na(s) 108 86 Sublimation of Rb(s) 158 Dissociation of F2(g Ionization energy of Na(g) 496 ionization energy of Rb(g) 403 Electron affinity of F(g) -322 Lattice enthalpy of NaF(s) 926 Lattice enthalpy of RbF(s) 789
Sodium fluoride (NaF) is a molecule formed by an ionic bond. a. The electron affinity of F is 3.40 eV and the ionization energy of Na is 5.14 eV. What is the transfer energy associated with this bond? b. The equilibrium separation of the Na and F atoms in the molecule is r_0 = 0.193 nm. What is the electrostatic potential energy of the atoms? c. The measured dissociation energy of NaF is 4.99 eV. Using the results above, what...
Determine the lattice energy (in kJ/mol) of NaF(s), using the data provided. Energy to sublime Na(s) = 109.0 kJ/mol Electron affinity of F(g) = -328.0 kJ/mol First ionization energy of Na(g) = 495.0 kJ/mol Bond energy of F2(g) = 154.0 kJ/mol ΔHrxn for Na(s) + 1/2 F2(g) → NaF(s) = -569.0 kJ/mol
Given the following information, calculate the lattice energy of CaF2 The enthalpy of formation of CaF2 -1228 kJ/mol Heat of sublimation of Ca 177.8 kJ/mol Bond dissociation energy of F2 159 kJ/mol First ionization energy of Ca 589.8 kJ/mol Second ionization energy of Ca 1145.4 kJ/mol . Electron affinity of F -328 kJ/mot [ Answer : -2644 KJİ I
Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol The first ionization energy of Na is IE1=496 kJ/mol. The electron affinity of Cl is ΔHEA=−349 kJ/mol. The bond energy of Cl2 is BE=243 kJ/mol. Determine the enthalpy of formation, ΔHf, for NaCl(s). ΔHf= kJ/mol
How does the ionization energy of the singly charged anion I− relate to the electron affinity of the neutral atom? A) The ionization energy of I− and the electron affinity of I are not related. B) The ionization energy of I− is half the electron affinity of I because the reaction is more favorable. C) The ionization energy of I− is the same magnitude as the electron affinity of I, but has the opposite sign. D) The ionization energy of...
10. Which of the following terms accurately describes the energy associated with the process: Li(g) → Lit(g) + € (a) Electron affinity (b) Binding energy (c) lonization energy (d) Electronegativity (e) None of these
2. Use the following data to calculate the lattice energy (U) of NaCl(s) from sodium me chlorine: Enthalpy of formation (4H) for NaCl(s) - -411 kJ/mol Enthalpy of sublimation (4Hub) of Na 107.3 kJ/mol The first ionization energy of Na (E,)-495.8 kJ/mol The bond dissociation energy (D) of Clh- 243 kJ/mol The electron affinity of Cl (Eea)- 348.6 kJ/mol.
Using the thermodynamic quantities shown below: construct a Born-Haber cycle for the following reaction: Li(s) + 1/2 F2(g) LiF(s); calculate the lattice energy of LiF. Vaporization of Li(s): +159 F2 bond enthalpy: +155 Li ionization energy: +520 F- electron affinity: +328 LiF(s) heat of formation: -616