53) How much energy is required to vaporize 48.7 g of dichloromethane (CH2Cl2) at its boiling...

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Answer 1

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Answer #1

Moles of dichloromethane = mass / molar mass = 48.7 / 85 = 0.573 moles

Heat needed = $\Delta$ H_vap * number of moles = 31.6 * 0.573 = 18.11 KJ, option C

Answer 2

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