How much energy is required tp vaporize 48.7 g pf dichloromethane at its boiling point, if...

Question

Question

How much energy is required tp vaporize 48.7 g pf dichloromethane at its boiling point, if tis Hvap is 31.6 kJ/mol?

Answer 1

Answer #1

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Answer 2

Answer #2

Moles of CH2Cl2 = mass/molar mass

= 48.7/84.93 = 0.5734 mol

Energy required = moles x ΔHvap

= 0.5734 x 31.6 = 18.1 kJ

Answer 3

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