Homework Answers
The concepts used to solve this problem is based on Baeyer-Villiger oxidation.
Firstly, the chemical reaction of cyclohexyl methyl ketone with peroxy acid is written. After that, the formation of the product is explained by the mechanism.
Baeyer-Villiger oxidation:
Baeyer-Villiger oxidation is an organic reaction that is used to convert ketone to an ester using a peroxy acid.
The reaction is illustrated as follows.
The more electron rich migrate to the oxygen. The order is given as follows.
The chemical reaction of cyclohexyl methyl ketone with peroxy acids as follows.
The mechanism for the formation of cyclohexyl acetate from the reaction cyclohexyl methyl ketone with a peroxy acid is shown below.
The main product formed from the Baeyer-Villiger oxidation of cyclohexyl methyl ketone is as follows.
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the Baeyer-Villiger oxidation of cyclohexyl methyl ketone, shown below, draw the main organic product.
For the Baeyer–Villiger oxidation of cyclohexyl methyl ketone, shown below, draw the main organic product. For...
For the Baeyer–Villiger oxidation of cyclohexyl methyl ketone,
shown below, draw the main organic product.
For the Baeyer-Villiger oxidation of cyclohexyl methyl ketone, shown below, draw the main organic product. acid Which group of cyclohexyl methyl ketone, the cyclohexyl or the methyl group, is a better migrating group? How does migration ability affect the position of oxygen insertion?
7. (5 points extra credit) Baeyer-Villiger Oxidation! When tert-butyl methyl ketone is reacted with mCPBA and...
7. (5 points extra credit) Baeyer-Villiger Oxidation! When tert-butyl methyl ketone is reacted with mCPBA and base, the ketone is cleanly converted to a single ester product in high yield (A or B). Circle the product of this reaction (A or B) and explain your answer (explain the migratory ability of t-Bu vs Me).
The protonated form of the intermediate in a Baeyer-Villiger oxidation is shown. Draw the structures of...
The protonated form of the intermediate in a Baeyer-Villiger oxidation is shown. Draw the structures of the two reactants in their neutral form. Draw the structures of the two products in their neutral form. Draw mechanistic curved arrows on the intermediate structure to show the flow of electrons as the intermediate breaks down to form products. The R: group represents a proton acceptor that will accept a proton from the positively charged intermediate so that the final products will be...
Can you draw out the mechanism steps for the Baeyer-Villiger Oxidation? proy autd onales of tr,floors...
Can
you draw out the mechanism steps for the Baeyer-Villiger Oxidation?
proy autd onales of tr,floors ochc a 13. 35
which one is true and which one is false ? T/F (7) In the Baeyer-Villiger oxidation,...
which one is true and which one is false ? T/F
(7) In the Baeyer-Villiger oxidation, the carbon migration will take place in both symmetric and asymmetric ketone or aldehyde. (17) Acyl chloride can be reduced by LAH or Grignard reagents to secondary alcohol.
The Baeyer-Villiger reaction is classified as an “oxidation” reaction. What is the chemical species that's being...
The Baeyer-Villiger reaction is classified as an “oxidation” reaction. What is the chemical species that's being oxidized in this reaction? What is the chemical species that is being reduced?_ Baeyer-Villiger Reaction of Acetophenone Data Results • Moles of acetophenone used: (Show calculations) 0.020 moles (2.40g/120.151 g mol-1 =0.0199 moles) • Moles of mCPBA used: (Show calculations) 0.036 moles_(6.25 grams/ 172.56 g.mol-1) • Expected mass of the product: (Show calculation. Clearly show the limiting and excess reactants)
Phenyl Acetate or Methyl Benzoate "C227 Baeyer-Villiger Reaction" 2 1.0000 0.4998 U.98.39 - M 7.4235 -...
Phenyl Acetate or Methyl Benzoate "C227 Baeyer-Villiger Reaction" 2 1.0000 0.4998 U.98.39 - M 7.4235 - M 7.2793 - M 7.1626 1 "C:\CHEM 227 SEC201 ss 1.5523 - M 2.3280 (ppm) O- - 10 20 30 40 40 50 [*166] Phenyl Acetate or Methyl Benzoate "C227 Baeyer-villiger Reaction" 2 7.5 1 1.0000 M 7.4390 - M 7.4182 M 7.4002 0.4998 M 7.2852 - M 7.2672 M 7.2465 "C:\CHEM 227 SEC201 ss" 0.9839 M 7.1523 M 7.1329 7.0 [ppm] TTTTTTTT 20...
Draw the correct organic product for the following oxidation reaction:
Draw the correct organic product for the following oxidation reaction:Predict the oxidation product of treating the given alkene with the reagent shown below. Include stereochemistry where applicable. Include H's on chirality centers. (mCPBA = meta-chloroperoxybenzoic acid)
Three isomeric ketones, compounds A, B, and C, with the molecular formula C_7H_14O are converted into...
Three isomeric ketones, compounds A, B, and C, with the molecular formula C_7H_14O are converted into heptane by Clemmensen reduction. Upon Baeyer-Villiger oxidation, compound A gives a single product; compound B gives two different products with very different yields; compound C gives two different products in virtually a 1:1 ratio. Deduce and draw A, B, and C in the labeled boxes below. Incorrect. The ketone you have drawn as compound B does fit the molecular formula and produces heptanes upon...
Draw the correct organic product of the following oxidation reaction: Draw the correct organic product of...
Draw the correct organic product of the following oxidation
reaction:
Draw the correct organic product of the following oxidation reaction: KCrO,/H2SO dis till or PCC/CH2C/25° C
For the Baeyer–Villiger oxidation of cyclohexyl methyl ketone,
shown below, draw the main organic product.
For the Baeyer-Villiger oxidation of cyclohexyl methyl ketone, shown below, draw the main organic product. acid Which group of cyclohexyl methyl ketone, the cyclohexyl or the methyl group, is a better migrating group? How does migration ability affect the position of oxygen insertion?
7. (5 points extra credit) Baeyer-Villiger Oxidation! When tert-butyl methyl ketone is reacted with mCPBA and base, the ketone is cleanly converted to a single ester product in high yield (A or B). Circle the product of this reaction (A or B) and explain your answer (explain the migratory ability of t-Bu vs Me).
The protonated form of the intermediate in a Baeyer-Villiger oxidation is shown. Draw the structures of the two reactants in their neutral form. Draw the structures of the two products in their neutral form. Draw mechanistic curved arrows on the intermediate structure to show the flow of electrons as the intermediate breaks down to form products. The R: group represents a proton acceptor that will accept a proton from the positively charged intermediate so that the final products will be...
Can
you draw out the mechanism steps for the Baeyer-Villiger Oxidation?
proy autd onales of tr,floors ochc a 13. 35
which one is true and which one is false ? T/F
(7) In the Baeyer-Villiger oxidation, the carbon migration will take place in both symmetric and asymmetric ketone or aldehyde. (17) Acyl chloride can be reduced by LAH or Grignard reagents to secondary alcohol.
The Baeyer-Villiger reaction is classified as an “oxidation” reaction. What is the chemical species that's being oxidized in this reaction? What is the chemical species that is being reduced?_ Baeyer-Villiger Reaction of Acetophenone Data Results • Moles of acetophenone used: (Show calculations) 0.020 moles (2.40g/120.151 g mol-1 =0.0199 moles) • Moles of mCPBA used: (Show calculations) 0.036 moles_(6.25 grams/ 172.56 g.mol-1) • Expected mass of the product: (Show calculation. Clearly show the limiting and excess reactants)
Phenyl Acetate or Methyl Benzoate "C227 Baeyer-Villiger Reaction" 2 1.0000 0.4998 U.98.39 - M 7.4235 - M 7.2793 - M 7.1626 1 "C:\CHEM 227 SEC201 ss 1.5523 - M 2.3280 (ppm) O- - 10 20 30 40 40 50 [*166] Phenyl Acetate or Methyl Benzoate "C227 Baeyer-villiger Reaction" 2 7.5 1 1.0000 M 7.4390 - M 7.4182 M 7.4002 0.4998 M 7.2852 - M 7.2672 M 7.2465 "C:\CHEM 227 SEC201 ss" 0.9839 M 7.1523 M 7.1329 7.0 [ppm] TTTTTTTT 20...
Three isomeric ketones, compounds A, B, and C, with the molecular formula C_7H_14O are converted into heptane by Clemmensen reduction. Upon Baeyer-Villiger oxidation, compound A gives a single product; compound B gives two different products with very different yields; compound C gives two different products in virtually a 1:1 ratio. Deduce and draw A, B, and C in the labeled boxes below. Incorrect. The ketone you have drawn as compound B does fit the molecular formula and produces heptanes upon...
Draw the correct organic product of the following oxidation
reaction:
Draw the correct organic product of the following oxidation reaction: KCrO,/H2SO dis till or PCC/CH2C/25° C
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Amplitude=3;
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