Question

Previous Problem Problem List Next Problem (1 point) The data set below shows a sample of student exam scores on a final examination. 70, 60, 64, 83, 34, 41, 61, 55, 78, 61, 45, 66, 32, 75, 48, 91, 46, 89, 98, 60, 83, 55, 37, 71, 90 - Part 1 Compute the following, give each answer to at least four decimal places. The mean of these scores is 63.72 The standard deviation of these scores is 18.9814 Part 2 In this data set Scores below EEwould be considered unusually low Scores above would be considered "unusually high." Preview My AnswersSubmit Answers You have atempted this probiem 4 tmes

Answer 1

Part -1: 2x 1593 Mean 63.72 25 = 8647.04 360.2933 Variance = n'ї Σ(X-X). 25-1 ( Standard deviation-Variance-360.2933 8647.04) - -24 18.9814 Part-2: Now, Z -score is, X-mean Standard deviation The Z-score less than-2 usually considered unusual Low Now, we have to calculate the corresponding X (Scores) whose z value is -2 -63.72 18.9814 2 (18.9814) x-63.72 -37.96279 =x-63.72 -3 7.96279 + 63.72 X=25.75721 Hence, sores below 25.75721 would be considered unusually low