Question

A passenger on a moving train walks at a speed of 2.30 m/s due north relative to the train. The train is traveling at 3.5 m/s due east relative to the ground. What are the magnitude and direction of the velocity of the passenger relative to the ground?

magnitude	m/s
direction	° north of east

Answer 1

Here,

let east is the positive x direction

north is the positive y direction

velocity of person relative to train , vpt = 2.3 j

velcity of train , vt = 3.5 i m/s

Now, for the velocity of person relative to ground

vp = vpt + vt

vp = 3.5 i + 2.3 j

vp = sqrt(3.5^2 + 2.3^2) at atan(2.3/3.5) degree north of east

vp = 4.19 m/s at 33.3 degree north of east

the velocity of person is 4.19 m/s at 33.3 degree north of east