Question

Find the following z values for the standard normal variable Z. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) P(Z z) 0.8605 a b. P(Z>z) 0.8018 c. P(-zs Z z) = 0.86 d. P(0 Zz) = 0.2235

Answer 1

SOIutiom aiven that using Stumlul herma tuble a) pCzez-0.8605 P(ZS108) 0.8605 7-1.08 b PZ7Z)0.8018 1-P(Zz)0.8D18 PCZZZDI-0 8D18 P(zz-o.85) 0.1982 -U 85 PCZZ-PCZE-Z)0.86 2P(247)-10.86 2P (z47)Ito.86 P(ZSZI 1.86 PIZEZEO93 P(z1.48) 2 o.93 2 72148

d P(o szとて): 0.2235 P(zZN-PCZCO)0.235 P(Zz o.5+0.2235 PIZSZE o235 p(zz0.59)=D1235 Zao.59