Question

find the following z values for the standard nor

Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) a. P(Z s z) = 0.8902 b. P(Z > z) = 0.742 C. Pl-z sz s z) = 0.97 d. POSZ sz) = 0.3509

Answer 1

sointium! using standard harms table a P(Z = z) = 0.8902 PC Z51.23) = 0.8902 2 = 1.23 Plz cz)=0.8902 = 1.23. b) P(Z > 2) = 6.742 I-P(Z < 2) = 0.742 P lecz) =1-0.742 P (2c-0.570285 I= -0.57 P(272) 20.742 = -0.57 c) P(-2 szez) = 0.97 P(Z < 2) -P (22-2)= 0.97 2P CZ 222 = It 0.97 PIZ22) 2 1.97/2 P(Z L2) = 0.985 P(Z 2 2.17 = 0.985 2 = 2.17 P(-222 (2) = 0.97 = 2.17

4) Post416 - 3569 P( t) -Р (26) - 04509 р (14) 2 Б-S+ p.3SD4 р() 20. 8569 р(:04) 2 6 - 8 54 12 | ОЧ р(о ) 20 - 3564 21:04