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A 91 kg man lying on a surface of negligible friction shoves a 68 g stone...

A 91 kg man lying on a surface of negligible friction shoves a 68 g stone away from himself, giving it a speed of 4.0 m/s. What speed does the man acquire as a result?
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Answer #1
Mass of the man, m1 = 91 kg

Mass of the stone, m2 = 68 g

= 0.068 kg

Speed of the man,v1 = ?

Speed of the stone, v2 = 4 m/s

According to the law of conservation of momentum,

Momentum of the man = Momentum of the stone

m1 v1 = m2 v2

91 * v1 = 0.068 * 4

Speed of the man, v1 = 0.003 m/s

Direction of the speed of the man: Opposite to the stone
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