Homework Answers
let,
mass of the person, m1=92 kg and velocity is v1
mass of the stone, m2=66 kg and velocity is v2=4 m/sec
by using law of conservation of momentum,
P_initial =P_final
0=m1*V1+m2*v2
===>
92*v1+(66*10^-3)*4=0
===> v2=2.87*10^-3 m/sec
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