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Reference the figure below to answer question 8. 8. F1 = 20 N, F2 - 40 N. F3 = 10 N. The 2-kg box is moved 0.6 m up the incli

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- we know that d=06m m 2 kg F=QON F2 = 40 F3 = lon d = 0.6m F,+ 50053. Free Body diagram 2 F2 30 fg+mgcos ama no mg + Fasinoc) ak done by Fy W 2012 - 10x 0-6 005 3. W = 5.19 Joule sin 30 = 1 ha desno = 0.68 0.5 . There is no friction so No Heat 20sssay that Co we can Wery + PE+KE = PEG + KEF Tw, WztWz) + PEot K&o = PEJ+KET 6. W, 12J; W2 = 0; Wz = 5.19 PE=0; KE = 0 (due to

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