For two events, A and B, P(A)=0.2, P(B)=0.5 and P(A|B=0.2.
a. Find P(A∩B)=
b. Find P(B|A).=
For two events, A and B, P(A)=0.2, P(B)=0.5 and P(A|B=0.2. a. Find P(A∩B)= b. Find P(B|A).=
p(b)= 0.5, p(c)=0.2, events b and c are mutually exclusive. find p( b intersects c)
A and B are two events such that P(A) = 0.4, P(B) = 0.5, and P(A|B) = 0.3. Find P(A and B). Select one: a. 0.6 b. 0.15 c. 0.12 d. 0.2
For two events, A and B, P(A=0.2, P(B)=0.50, and P(A|B)=0.2. a. Find P(A∩B) .b. Find P(B|A). (Simplify your answer) b. P(B|A)=__________(Simplify your answer.)
Two events A and B are such that P(A) = 0.4, P(B) = 0.5, and P(AUB) = 0.7. (a) Find P(A n B). 0.2 (b) Find P(AUB). 0.8 (c) Find P(An B). 0.3 (d) Find P(AB). (Enter your probability as a fraction.) 1/2
let A and B be any 2 events with p(A)=0.2; P(AUB)=0.35; P(A and B)= 0.15 find P(A|B) QUESTION 25 Let A and B be any 2 events with p(A) 0.2; P(AUB) 0.35; P(A and B) 0.15 a.0.25 Find P(A|B) b.0.5 c.0.6 d.0.4
Let P(A) = 0.4 P(B) = 0.5 P(A|B) = 0.2 (Please show working). If the events a and b are independent, calculate the P(A and B) If the events a and b are not independent, calculate the P(A and B) If the events a and b are mutually exclusive, calculate the P(A or B)
0.2 Question 7 (1 point) <Venn 3> There are 2 events: A, B with P(A)-0.5, P(B)-0.4, P(AUB)-0.7 Find P(BA) (2 decimal places without rounding-up) Question 8 (1 point) Saved <Venn 4>
A 0.2 В 0.5 0.1 Given the events A and B above, find the following probabilities P(A and B) P(A or B) P(A | B) P(B | A) = P( not A and B) = P(A and not B) Are events A and B independent (yes Explain why or why not or no) Are events A and B independent (yes Explain why or why not or no) GRB 5/5/2019 Math 121 Final Spring 2019
Classify the events as dependent or independent: Events A and B where P(A) = 0.5, P(B) = 0.2, and P(A and B) = 0.09 Independent or Dependent? 0.5 x 0.2=0.10 which does not equal 0.09, does this mean that the correct answer is dependent?
Consider three random events, A, B and C. Suppose that P(A) = 0.5, P(A∩C) = 0.2, P(C) = 0.4, P(B) = 0.4, P(A∩B∩C) = 0.1, P(B∩C) = 0.18, and P(A∩B) = 0.21. Calculate the following probabilities: c. P((B∩C)c ∪(A∩B)c)