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How many grams of CaCl, are needed to make 974.0 g of a solution that is 37.0% (m/m) CaCl, in water? Note that mass is not te

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Answer #1

371 of 974g = 318 974 = 360.38 grom of Caela - 360.28 - ter 974. 360.28 - 613 61g water mass of Calle = 360.38 g mass of wate

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