Question

How many grams of CaCl, are needed to make 741.8 g of a solution that is 38.0% (m/m) CaCl, in water? Note that mass is not technically the same thing as weight, but % (m/m) has the same meaning as % (w/w). grams CaCl, = How many grams of water are needed to make this solution? grams H,0 =

Answer 1

Dear Student, Kindly refer to the complete solution. Feel free to ask if you face difficulty in understanding any step of the solution attached, so that we can assist you in a better way.

Page Deal Student 38% (m/m) means 38g of cache is present in 100g of solution. Thus, 100 g g solution has 38 g of cacle 18 of solution → 38 g of calls 100 • 74108 g of solution will have 38 x 74 1.8 g of cache 38 x 741.8 F = 281.884 g of Calle Total mass of solution - mass of Colla + mass of Ho Thus grams of water added - 741.89 - 281.8848 = 459.916 g Best wishes!!