Homework Answers
Potential at the surface of a sphere is given by:
V = k*Q/R
V = Potential = 1.82*10^5 V
k = electrostatic constant = 9*10^9
Q = Charge on sphere = 8.70*10^-8 C
R = radius of sphere = ?
Using known values:
R = k*Q/V
R = 9*10^9*8.70*10^-8/(1.82*10^5)
R = 4.30*10^-3 m
Now Surface area of spherical drop is given by:
S = 4*pi*R^2
S = 4*pi*(4.30*10^-3)^2
S = 2.32*10^-4 m^2
S = 2.32E-4 m^2
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