(a) From the figure, we see that the lever arm of bucket 1 is shorter therefore, bucket 1 holds more water.
So, third option is the correct answer.
(b) Now, assume the weight of the water in bucket 2 is 10 N
Let A be the additional weight of water in bucket 1
sum moments about the balance point to zero.
Therefore,
10[(1.35 / 2) + 0.0175] - (10 + A)[(1.35 / 2) - 0.0175] = 0
=> 10[(1.35 / 2) + 0.0175] = (10 + A)[(1.35 / 2) - 0.0175]
=> 10[ 0.6925] = (10 + A)[0.6575]
=> 6.925 = 6.575 + 0.6575*A
=> 0.6575*A = 0.35
=> A = 0.35 / 0.6575
= 0.532 N
In percentage, bucket 1 contains (0.532/10) x 100 = 5.32 % more water than in bucket 2.
Resources Go While on a camping trip, a man would like to carry water from the...
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While on a camping trip, a man would like to carry water from the lake to his campsite. He fills two, non‑identical buckets with water and attaches them to a 1.67 m long rod. Since the buckets are not identical, he finds that the rod balances about a point located at a length ?=0.0271 m from its midpoint, as shown. The weight of the rod and empty buckets is negligible compared to the weight of the water, and the buckets are not shown to scale.