Question

Find the equivalent resistance of the combination of resistors?1=42.0 ΩR1=42.0 Ω , ?2=75.0 ΩR2=75.0 Ω , ?3=33.0 ΩR3=33.0 Ω , ?4=61.0 ΩR4=61.0 Ω , ?5=13.5 ΩR5=13.5 Ω , and ?6=31.0 ΩR6=31.0 Ω , as shown in the figure.

4 R,

Answer 1

R_1, R_2 in parallel = > R�_eq = R_1 R_2/R_1 + R_2 R�_eq = 42 times 75/75 + 42 R�_2 = 26.92 Ohm R_1 = 42 Ohm R_2 = 75 Ohm R_3 = 33 Ohm R_4 = 61 Ohm R_5 = 13.5 Ohm R_6 = 31 Ohm R�_2, R_3, R_4 in series so equivalent of all three R�_3 = R�_2 + R_3 + R_4 = > 26.92 + 33 + 61 R�_3 = 120.92 Ohm R�_3 and R_5 in parallel equivalent of both R�_4 = R�_3 R_5/R�_3 + R_5 R�_4 = 12.144 Ohm R�_4, R_6 in series = 12.144 + 31 R_eq = 43.144 Ohm