Question

Consider a large population of interest. It's distribution is normal and it's mean is 184 and standard deviation is 109. Let X = a single observation.

(Round all probabilities to four decimals)

Consider a large population of interest. It's distribution is normal and it's mean is 184 and standard deviation is 109, Let X = a single observation (Round all probabilities to four decimals) a) Find P(X 189): le of 132 is taken. Let X = sample average of the observations b) Find P(X< 189): Consider another large population of interest. It's distribution is unknown and it's mean is 184 and it standard deviation is 109. Let Y - a single observation. le of 132 is taken. Let Y = sample average of the observations c) Find P(Y 189):

Answer 1

- Giverthat-xN 109 standard deviation-(c) a P(x 18) PX-189-18 jog bsample size (n) 132 09/J132 and 6-10g s mple size (n) = 132 Since, sample size is lavge (ie. 7 30) the Sampling distibahon of sample mean () is normal Theve fore 1O09/5132 P(でく0:53)