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Some potentially useful information: cal c(water) 1.0 Ltusion (water)- 80 cal & k cal c(ice) 0.49 Lvap (water)- 540 cal gK 1. Last week we took a look at this problem and only required a qualitatively correct response. Most of you did a good job of breaking the overall process into three distinct portions. This week we built on some of those ideas and are in a better position to be more quantitative. As you revisit this problem, pay attention to details such as which portions of the overall process require more energy. Assuming the microwave is transferring energy at a constant rate allows us to view the time axis as an energy input axis An Ice cube at a temperature of -20 °C is put in a plastic bowl and which is then placed in a microwave oven, and the oven is turned on. When the oven is turned off, the bowl contains water that is at a temperature of 60 °C. Assuming the microwave transferred energy to the ice at a constant rate throughout, draw a graph (below) of the temperature of the H2O as a function of time. The endpoints of the graph are given. Finish: Water, 60 °C time (s) Start: Ice,-20 °C ain why your graph looks the way it does.
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o.5 1.5 time tS) x7.5 uult time 4.00 uuìセtime. unt

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