Use Bayes's Theorem to calculate the probability prompted for in the following scenario. Indicate your answer as a percentage. Type your numeric answer into the space provided.
Your cousin Jeffrey studies for final exams 75 percent of the time. When Jeffrey studies for a final exam, he receives a grade of B or higher 80 percent of the time. When Jeffrey does not study for a final exam, he receives a grade of B or higher only 60 percent of the time.
Apply Bayes's Theorem to the scenario just described. If Jeffrey receives a grade of B or higher on his next final exam, what is the probability that he studied for the exam (expressed as a percentage)?
Let E shows the event that Jeffrey studies for final exams. And G shows the event that he receives a grade of B or higher.
From given information we have
P(E ) = 0.75, P(E') = 1- P(E) = 1 - 0.75 = 0.25
P(G | E) = 0.80, P(G |E' ) = 0.60
Now by the Bayes's Theorem, the probability that he studied for the exam (expressed as a percentage) is
P(E | G) = [ P(G|E)P(E) ] / [ P(G|E)P(E) + P(G|E')P(E') ] = [ 0.80 * 0.75] / [ 0.80 * 0.75 + 0.60 * 0.25] = 0.60 / 0.75 = 0.80
Answer: 80%
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