a. Obtain the linear trend equation for the following data on new checking accounts at Fair Savings Bank and use it to predict expected new checking accounts for periods 16 through 19. (Round your intermediate calculations and final answers to 2 decimal places.)
Period | New Accounts | Period | New Accounts | Period | New Accounts |
1 | 200 | 6 | 239 | 11 | 281 |
2 | 212 | 7 | 243 | 12 | 275 |
3 | 211 | 8 | 250 | 13 | 287 |
4 | 222 | 9 | 251 | 14 | 288 |
5 | 235 | 10 | 267 | 15 | 316 |
Y | = | + | t | |
Y16 | = | |||
Y17 | = | |||
Y18 | = | |||
Y19 | = | |||
b.Use trend-adjusted smoothing with α = .2 and β =
.1 to smooth the new account data in part a. What is the forecast
for period 16? Compute the initial trend estimate (Tt)
for Period 5 as follows: (Period 4 data – Period 1 data) / 3. Then
compute the initial trend-adjusted forecast (TAFt) for
Period 5 as follows: Period 4 data + Initial trend estimate for
Period 5. Then compute all remaining values (including the
St value for Period 5) using the textbook formulas or
Excel template. (Round the "Trend"values (Tt) to 3 decimal
places and all other intermediate forecast values (TAFt and St) to
2 decimal places. Round your final answer to 2 decimal
places.)
Forecast for period 16 =___
a)
Period(x) |
New Accounts(y) |
xy |
x2 |
|
1 |
200 |
200 |
1 |
|
2 |
212 |
424 |
4 |
|
3 |
211 |
633 |
9 |
|
4 |
222 |
888 |
16 |
|
5 |
235 |
1175 |
25 |
|
6 |
239 |
1434 |
36 |
|
7 |
243 |
1701 |
49 |
|
8 |
250 |
2000 |
64 |
|
9 |
251 |
2259 |
81 |
|
10 |
267 |
2670 |
100 |
|
11 |
281 |
3091 |
121 |
|
12 |
275 |
3300 |
144 |
|
13 |
287 |
3731 |
169 |
|
14 |
288 |
4032 |
196 |
|
15 |
316 |
4740 |
225 |
|
Total |
120 |
3777 |
32278 |
1240 |
x-bar = Sum(x)/n = 120/15 = 8
y-bar = Sum(y)/n = 3777/15 = 251.8
b = (Sum(xy) – n*x-bar*y-bar)/(Sum(x2) – n*x-bar*x-bar)
= (32278-15*8*251.8)/(1240–15*8*8)
= 2062/280 = 7.364285714 = 7.36 (Rounded to 2 decimal place)
a = y-bar –b*x-bar
= 251.8 - 7.36*8 = 192.92
Regression equation is y = a + bx,
we get following linear trend equation by substituting values of a
and b
Regression equation is y =192.92+7.36x
Y16 = 192.92+7.36*16 = 310.68
Y17 = 192.92+7.36*17 = 318.04
Y18 = 192.92+7.36*18 = 325.4
Y19 = 192.92+7.36*19 = 332.76
b)
Period(t) |
New Accounts(A(t)) |
S(t) |
T(t) |
TAF(t) |
1 |
200 |
|||
2 |
212 |
|||
3 |
211 |
|||
4 |
222 |
|||
5 |
235 |
222 |
7.333 |
229.33 |
6 |
239 |
230.46 |
7.446 |
237.91 |
7 |
243 |
238.13 |
7.468 |
245.60 |
8 |
250 |
245.08 |
7.416 |
252.50 |
9 |
251 |
252 |
7.366 |
259.37 |
10 |
267 |
257.70 |
7.199 |
264.90 |
11 |
281 |
265.32 |
7.241 |
272.56 |
12 |
275 |
274.25 |
7.410 |
281.66 |
13 |
287 |
280.33 |
7.277 |
287.61 |
14 |
288 |
287.49 |
7.265 |
294.76 |
15 |
316 |
293.41 |
7.130 |
300.54 |
303.63 |
7.439 |
311.07 |
Using trend adjusted exponential smoothing, F(t) = TAF(t-1) + alpha*(A(t-1) - TAF(t-1))
T(t) = T(t-1) + beta*(F(t) - TAF(t-1))
and TAF(t) = F(t) + T(t)
Forecast for period 16 = 311.07
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