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what is the magnitude of the potential difference needed to give an alpha particle (composed of 2 protons and 2 neutrons) 239.0 keV of kinetic energy? Answer] incompatible units. No conversion found between-ker and the required units. Tries 1/99 Press ustes Post Discussion
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Answer #1

Kinetic energy = qV

where q = charge

V = potential difference

239*1.6*10^-16 = 2*1.6*10^-19*V

V = 119500 volts

so the magnitude of potential difference is 1.195*10^5 V

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