The concept used to solve this problem is kinetic energy of the particle, work done on a charged particle in an electric field, and work-energy theorem.
Initially, calculate the work done on the alpha particle using work done on a charged particle in an electric field, then find the change in kinetic energy of the alpha particle using the expression of kinetic energy and finally according to the work-energy theorem equate this change in kinetic energy to the work done to find final kinetic energy.
The work done on a charged particle in moving a particle in electric field is,
Here, W is the work done, is the potential difference, and q is the charge of the particle.
According to Work-Energy theorem, work done is equal to the change in the kinetic energy.
Here, is the change in the kinetic energy.
The kinetic energy of the particle is,
Here, K is the kinetic energy, m is the mass of the particle, and v is the velocity of the particle.
Calculate the work done on the alpha particle as follows:
The work done on a charged particle in moving a particle in electric field is,
Substitute 350 V for and for q.
Calculate the change in kinetic energy of the alpha particle as follows:
The initial kinetic energy () of the particle is,
Here, m is the mass of the particle and is the initial velocity.
Substitute 0 m/s for .
The change in kinetic energy () of the particle is,
Here, is the final kinetic energy.
Substitute 0 J for .
Calculate the final kinetic energy of the alpha particle as follows:
According to Work-Energy theorem, work done is equal to the change in the kinetic energy.
Here, is the change in the kinetic energy.
Substitute for and for W.
Ans:
The final kinetic energy of the particle is.
The potential difference between two parallel conducting plates in vacuum is 350 V. An alpha particle...
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